Spring MVC - 属性方法名称解析器示例


以下示例展示了如何使用 Spring Web MVC 框架使用多操作控制器的属性方法名称解析器方法。MultiActionController类有助于在单个控制器中分别映射多个 URL 及其方法

package com.tutorialspoint;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

public class UserController extends MultiActionController{
	
   public ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Home");
      return model;
   }

   public ModelAndView add(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Add");
      return model;
   }

   public ModelAndView remove(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Remove");
      return model;
   }
}
<bean class = "com.tutorialspoint.UserController">
   <property name = "methodNameResolver">
      <bean class = "org.springframework.web.servlet.mvc.multiaction.PropertiesMethodNameResolver">
         <property name = "mappings">
            <props>
               <prop key = "/user/home.htm">home</prop>
               <prop key = "/user/add.htm">add</prop>
               <prop key = "/user/remove.htm">update</prop>	  
            </props>
         </property>
      </bean>
   </property>
</bean>

例如,使用上面的配置,如果 URI -

  • 请求 /user/home.htm 时,DispatcherServlet 会将请求转发给 UserController home()方法。

  • 请求 /user/add.htm 时,DispatcherServlet 会将请求转发给 UserController add()方法。

  • 请求/user/remove.htm时,DispatcherServlet会将请求转发给UserController的remove()方法。

首先,让我们准备一个可用的 Eclipse IDE,并考虑以下步骤来使用 Spring Web 框架开发基于动态表单的 Web 应用程序。

描述
1 按照 Spring MVC - Hello World 章节中的说明,在 com.tutorialspoint 包下创建一个名为 TestWeb 的项目。
2 在 com.tutorialspoint 包下创建 Java 类 UserController。
3 在jsp子文件夹下创建一个视图文件user.jsp。
4 最后一步是创建源文件和配置文件的内容并导出应用程序,如下所述。

用户控制器.java

package com.tutorialspoint;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

public class UserController extends MultiActionController{
	
   public ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Home");
      return model;
   }

   public ModelAndView add(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Add");
      return model;
   }

   public ModelAndView remove(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Remove");
      return model;
   }
}

TestWeb-servlet.xml

<beans xmlns = "http://www.springframework.org/schema/beans"
   xmlns:context = "http://www.springframework.org/schema/context"
   xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation = "
   http://www.springframework.org/schema/beans     
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context 
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name = "prefix" value = "/WEB-INF/jsp/"/>
      <property name = "suffix" value = ".jsp"/>
   </bean>

   <bean class = "org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"> 
      <property name = "caseSensitive" value = "true" />
   </bean>
   <bean class = "com.tutorialspoint.UserController">
      <property name = "methodNameResolver">
         <bean class = "org.springframework.web.servlet.mvc.multiaction.PropertiesMethodNameResolver">
            <property name = "mappings">
               <props>
                  <prop key = "/user/home.htm">home</prop>
                  <prop key = "/user/add.htm">add</prop>
                  <prop key = "/user/remove.htm">update</prop>	  
               </props>
            </property>
         </bean>
      </property>
   </bean>  
</beans>

用户.jsp

<%@ page contentType = "text/html; charset = UTF-8" %>
<html>
   <head>
      <title>Hello World</title>
   </head>
   <body>
      <h2>${message}</h2>  
   </body>
</html>

创建源文件和配置文件后,导出您的应用程序。右键单击您的应用程序,使用Export → WAR File选项并将TestWeb.war文件保存在 Tomcat 的 webapps 文件夹中。

现在,启动 Tomcat 服务器并确保您能够使用标准浏览器从 webapps 文件夹访问其他网页。现在,尝试一个 URL - http://localhost:8080/TestWeb/user/add.htm,如果 Spring Web 应用程序一切正常,我们将看到以下屏幕。

弹簧多动作控制器