数据结构和算法 - 链表

如果数组容纳相似类型的数据类型，则链表由具有不同数据类型的元素组成，这些元素也按顺序排列。

但这些链表是如何创建的呢？

链表是通过链接连接在一起的“节点”的集合。这些节点由要存储的数据和指向链表中下一个节点的地址的指针组成。对于数组，大小受定义限制，但在链表中，没有定义的大小。任意数量的数据都可以存储在其中，也可以从中删除。

链表分为三种类型 -

单链表- 节点仅指向列表中下一个节点的地址。
双向链表- 节点指向前一个和下一个节点的地址。
循环链表- 列表中的最后一个节点将指向列表中的第一个节点。它可以是单链的，也可以是双链的。

链表表示

链表可以看作是节点链，其中每个节点都指向下一个节点。

根据上图，以下是需要考虑的要点。

链表包含一个称为第一个（头）的链接元素。
每个链接都带有一个数据字段和一个称为 next 的链接字段。
每个链接都使用其下一个链接与其下一个链接链接。
最后一个链接带有一个空链接来标记列表的结尾。

链表的类型

以下是各种类型的链表。

单链表

单链表在一个节点中包含两个“桶”；一个桶保存数据，另一个桶保存列表的下一个节点的地址。遍历只能在一个方向上完成，因为同一列表的两个节点之间只有一条链接。

双向链表

双向链表在一个节点中包含三个“桶”；一个桶保存数据，其他桶保存列表中前一个和下一个节点的地址。由于列表中的节点从两侧相互连接，因此列表被遍历两次。

循环链表

循环链表可以存在于单链表和双向链表中。

由于循环链表的最后一个节点和第一个节点是相连的，所以这个链表中的遍历会一直进行下去，直到被破坏。

链表中的基本操作

链表中的基本操作是插入、删除、搜索、显示和删除给定键处的元素。这些操作在单链表上执行，如下所示 -

插入- 在列表的开头添加一个元素。
删除- 删除列表开头的元素。
显示- 显示完整列表。
搜索- 使用给定键搜索元素。
删除- 使用给定键删除元素。

插入操作

在链表中添加新节点是一项多步骤的活动。我们将在这里通过图表来了解这一点。首先，使用相同的结构创建一个节点并找到它必须插入的位置。

想象一下，我们在 A（左节点）和 C（右节点）之间插入一个节点 B（新节点）。然后指向 C 旁边的 B. -

NewNode.next −> RightNode;

它应该看起来像这样 -

现在，左侧的下一个节点应该指向新节点。

LeftNode.next −> NewNode;

这会将新节点放在两个节点的中间。新列表应如下所示 -

可以通过三种不同的方式完成链表中的插入。它们的解释如下 -

在开头插入

在此操作中，我们在列表的开头添加一个元素。

算法

1. START
2. Create a node to store the data
3. Check if the list is empty
4. If the list is empty, add the data to the node and assign the head pointer to it.
5 If the list is not empty, add the data to a node and link to the current head. Assign the head to the newly added node.
6. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");
   
   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){
   
   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   
   // point it to old first node
   lk->next = head;
   
   //point first to new first node
   head = lk;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(44);
   insertatbegin(50);
   printf("Linked List: ");
   
   // print list
   printList();
}

输出

Linked List: 
[ 50  44  30  22  12 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   cout << "\n[";
   
   //start from the beginning
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
   cout << "]";
}

//insertion at the beginning
void insertatbegin(int data){
   
   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   
   // point it to old first node
   lk->next = head;
   
   //point first to new first node
   head = lk;
}
int main(){
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(44);
   insertatbegin(50);
   cout << "Linked List: ";
   
   // print list
   printList();
}

输出

Linked List: 
[ 50  44  30  22  12 ]

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;
   
   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");
   
      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }

   //insertion at the beginning
   static void insertatbegin(int data) {

      //create a link
      node lk = new node(data);;

      // point it to old first node
      lk.next = head;

      //point first to new first node
      head = lk;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatbegin(44);
      insertatbegin(50);
      insertatbegin(33);
      System.out.println("Linked List: ");
      
      // print list
      printList();
   }
}

输出

Linked List: 

[33  50  44  30  22  12 ]

class Node:
   def __init__(self, data=None):
      self.data = data
      self.next = None
class SLL:
   def __init__(self):
      self.head = None

# Print the linked list
   def listprint(self):
      printval = self.head
      print("Linked List: ")
      while printval is not None:
         print (printval.data)
         printval = printval.next
   def AddAtBeginning(self,newdata):
      NewNode = Node(newdata)

      # Update the new nodes next val to existing node
      NewNode.next = self.head
      self.head = NewNode

l1 = SLL()
l1.head = Node("731")
e2 = Node("672")
e3 = Node("63")

l1.head.next = e2
e2.next = e3

l1.AddAtBeginning("122")
l1.listprint()

输出

Linked List: 
122
731
672
63

在结尾处插入

在此操作中，我们在列表末尾添加一个元素。

算法

1. START
2. Create a new node and assign the data
3. Find the last node
4. Point the last node to new node
5. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");
   
   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;
   
   //point first to new first node
   head = lk;
}
void insertatend(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   struct node *linkedlist = head;

   // point it to old first node
   while(linkedlist->next != NULL)
      linkedlist = linkedlist->next;

   //point first to new first node
   linkedlist->next = lk;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatend(22);
   insertatend(30);
   insertatend(44);
   insertatend(50);
   printf("Linked List: ");
   
   // print list
   printList();
}

输出

Linked List:
[ 12 22 30 44 50 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   cout << "\n[";
   
   //start from the beginning
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
   cout << "]";
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void insertatend(int data){
   
   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   struct node *linkedlist = head;

   // point it to old first node
   while(linkedlist->next != NULL)
      linkedlist = linkedlist->next;

   //point first to new first node
   linkedlist->next = lk;
}
int main(){
   insertatbegin(12);
   insertatend(22);
   insertatbegin(30);
   insertatend(44);
   insertatbegin(50);
   cout << "Linked List: ";

   // print list
   printList();
}

输出

Linked List: 
[ 50  30  12  22  44 ]

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;

   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");

      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }

   //insertion at the beginning
   static void insertatbegin(int data) {

      //create a link
      node lk = new node(data);;

      // point it to old first node
      lk.next = head;

      //point first to new first node
      head = lk;
   }
   static void insertatend(int data) {
   
      //create a link
      node lk = new node(data);
      node linkedlist = head;

      // point it to old first node
      while(linkedlist.next != null)
         linkedlist = linkedlist.next;

      //point first to new first node
      linkedlist.next = lk;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatend(44);
      insertatend(50);
      insertatend(33);
      System.out.println("Linked List: ");

      // print list
      printList();
   }
}

输出

Linked List: 
[ 30  22  12  44 50  33 ]

class Node:
   def __init__(self, data=None):
      self.data = data
      self.next = None
class LL:
   def __init__(self):
      self.head = None
   def listprint(self):
      val = self.head
      print("Linked List:")
      while val is not None:
         print(val.data)
         val = val.next

l1 = LL()
l1.head = Node("23")
l2 = Node("12")
l3 = Node("7")
l4 = Node("14")
l5 = Node("61")

# Linking the first Node to second node
l1.head.next = l2

# Linking the second Node to third node
l2.next = l3
l3.next = l4
l4.next = l5
l1.listprint()

输出

Linked List:
23
12
7
14
61

在给定位置插入

在此操作中，我们在列表中的任意位置添加一个元素。

算法

1. START
2. Create a new node and assign data to it
3. Iterate until the node at position is found
4. Point first to new first node
5. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");
   
   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void insertafternode(struct node *list, int data){
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   lk->next = list->next;
   list->next = lk;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertafternode(head->next, 30);
   printf("Linked List: ");

   // print list
   printList();
}

输出

Linked List:
[ 22 12 30 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   cout << "\n[";
   
   //start from the beginning
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
   cout << "]";
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void insertafternode(struct node *list, int data){
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   lk->next = list->next;
   list->next = lk;
}
int main(){
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertafternode(head->next,44);
   insertafternode(head->next->next, 50);
   cout << "Linked List: ";

   // print list
   printList();
}

输出

Linked List: 
[ 30  22  44  50  12 ]

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;

   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");

      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }

   //insertion at the beginning
   static void insertatbegin(int data) {

      //create a link
      node lk = new node(data);;

      // point it to old first node
      lk.next = head;

      //point first to new first node
      head = lk;
   }
   static void insertafternode(node list, int data) {
      node lk = new node(data);
      lk.next = list.next;
      list.next = lk;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatbegin(44);
      insertafternode(head.next, 50);
      insertafternode(head.next.next, 33);
      System.out.println("Linked List: ");

      // print list
      printList();
   }
}

输出

Linked List: 

[44  30  50  33  22  12 ]

class Node:
   def __init__(self, data=None):
      self.data = data
      self.next = None

class SLL:
   def __init__(self):
      self.head = None

# Print the linked list
   def listprint(self):
      printval = self.head
      print("Linked List: ")
      while printval is not None:
         print (printval.data)
         printval = printval.next

   # Function to add node
   def InsertAtPos(self,nodeatpos,newdata):
      if nodeatpos is None:
         print("The mentioned node is absent")
         return
      NewNode = Node(newdata)
      NewNode.next = nodeatpos.next
      nodeatpos.next = NewNode

l1 = SLL()
l1.head = Node("731")
e2 = Node("672")
e3 = Node("63")

l1.head.next = e2
e2.next = e3

l1.InsertAtPos(l1.head.next, "122")
l1.listprint()

输出

Linked List: 
731
672
122
63

删除操作

删除也是一个多步骤的过程。我们将通过图示来学习。首先，通过搜索算法找到要删除的目标节点。

目标节点的左（前一个）节点现在应该指向目标节点的下一个节点 -

LeftNode.next −> TargetNode.next;

这将删除指向目标节点的链接。现在，使用以下代码，我们将删除目标节点所指向的内容。

TargetNode.next −> NULL;

我们需要使用删除的节点。我们可以将其保留在内存中，否则我们可以简单地释放内存并完全擦除目标节点。

如果将节点插入到列表的开头，则应采取类似的步骤。在末尾插入时，链表的倒数第二个节点应指向新节点，并且新节点将指向 NULL。

链表中的删除也可以通过三种不同的方式执行。它们如下 -

开头删除

在链接的删除操作中，我们从列表的开头删除一个元素。为此，我们将头指向第二个节点。

算法

1. START
2. Assign the head pointer to the next node in the list
3. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");
   
   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void deleteatbegin(){
   head = head->next;
}
int main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(40);
   insertatbegin(55);
   printf("Linked List: ");
   
   // print list
   printList();
   deleteatbegin();
   printf("\nLinked List after deletion: ");
   
   // print list
   printList();
}

输出

Linked List: 
[ 55  40  30  22  12 ]
Linked List after deletion: 
[ 40  30  22  12 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   cout << "\n[";
   
   //start from the beginning
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
   cout << "]";
}

//insertion at the beginning
void insertatbegin(int data){
   
   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void deleteatbegin(){
   head = head->next;
}
int main(){
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(44);
   insertatbegin(50);
   cout << "Linked List: ";

   // print list
   printList();
   deleteatbegin();
   cout << "Linked List after deletion: ";
   printList();
}

输出

Linked List: 
[ 50  44  30  22  12 ]
Linked List after deletion: 
[ 44  30  22  12 ]

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;
   
   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");
      
      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }
   
   //insertion at the beginning
   static void insertatbegin(int data) {

      //create a link
      node lk = new node(data);;
      
      // point it to old first node
      lk.next = head;
      
      //point first to new first node
      head = lk;
   }
   static void deleteatbegin() {
      head = head.next;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatbegin(44);
      insertatbegin(50);
      insertatbegin(33);
      System.out.println("Linked List: ");
      
      // print list
      printList();
      deleteatbegin();
      System.out.println("\nLinked List after deletion: ");
      
      // print list
      printList();
   }
}

输出

Linked List: 
[ 33  50  44  30  22  12 ]
Linked List after deletion: 

[50  44  30  22  12 ]

#python code for deletion at beginning using linked list.
from typing import Optional
class Node:
    def __init__(self, data: int, next: Optional['Node'] = None):
        self.data = data
        self.next = next
class LinkedList:
    def __init__(self):
        self.head = None
     #display the list
    def print_list(self):
        p = self.head
        print("\n[", end="")
        while p:
            print(f" {p.data} ", end="")
            p = p.next
        print("]")
     #Insertion at the beginning
    def insert_at_begin(self, data: int):
        lk = Node(data)
         #point it to old first node
        lk.next = self.head
        #point firt to new first node
        self.head = lk
    def delete_at_begin(self):
        self.head = self.head.next
if __name__ == "__main__":
    linked_list = LinkedList()
    linked_list.insert_at_begin(12)
    linked_list.insert_at_begin(22)
    linked_list.insert_at_begin(30)
    linked_list.insert_at_begin(44)
    linked_list.insert_at_begin(50)
    #print list
    print("Linked List: ", end="")
    linked_list.print_list()
    linked_list.delete_at_begin()
    print("Linked List after deletion: ", end="")
    linked_list.print_list()

输出

Linked List: 
[ 50  44  30  22  12 ]
Linked List after deletion: 
[ 44  30  22  12 ]

结束时删除

在链接的删除操作中，我们从列表末尾删除一个元素。

算法

1. START
2. Iterate until you find the second last element in the list.
3. Assign NULL to the second last element in the list.
4. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");
   
   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){
   
   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void deleteatend(){
   struct node *linkedlist = head;
   while (linkedlist->next->next != NULL)
      linkedlist = linkedlist->next;
   linkedlist->next = NULL;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(40);
   insertatbegin(55);
   printf("Linked List: ");
   
   // print list
   printList();
   deleteatend();
   printf("\nLinked List after deletion: ");
   
   // print list
   printList();
}

输出

Linked List: 
[ 55  40  30  22  12 ]
Linked List after deletion: 
[ 55  40  30  22 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// Displaying the list
void printList(){
   struct node *p = head;
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
}

// Insertion at the beginning
void insertatbegin(int data){
   
   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;
   
   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void deleteatend(){
   struct node *linkedlist = head;
   while (linkedlist->next->next != NULL)
      linkedlist = linkedlist->next;
   linkedlist->next = NULL;
}
int main(){
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(44);
   insertatbegin(50);
   cout << "Linked List: ";

   // print list
   printList();
   deleteatend();
   cout << "\nLinked List after deletion: ";
   printList();
}

输出

Linked List:  50  44  30  22  12 
Linked List after deletion:  50  44  30  22

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;
   
   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");
      
      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }
   
   //insertion at the beginning
   static void insertatbegin(int data) {
      
      //create a link
      node lk = new node(data);;
      
      // point it to old first node
      lk.next = head;

      //point first to new first node
      head = lk;
   }
   static void deleteatend() {
      node linkedlist = head;
      while (linkedlist.next.next != null)
         linkedlist = linkedlist.next;
      linkedlist.next = null;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatbegin(44);
      insertatbegin(50);
      insertatbegin(33);
      System.out.println("Linked List: ");

      // print list
      printList();

      //deleteatbegin();
      deleteatend();
      System.out.println("\nLinked List after deletion: ");

      // print list
      printList();
   }
}

输出

Linked List: 
[ 33  50  44  30  22  12 ]
Linked List after deletion: 

[ 33  50  44  30  22 ]

#python code for deletion at beginning using linked list.
class Node:
    def __init__(self, data=None):
        self.data = data
        self.next = None
class LinkedList:
    def __init__(self):
        self.head = None
 #Displaying the list
    def printList(self):
        p = self.head
        print("\n[", end="")
        while p != None:
            print(" " + str(p.data) + " ", end="")
            p = p.next
        print("]")
 #Insertion at the beginning
    def insertatbegin(self, data):
        #create a link
        lk = Node(data)
        #point it to old first node
        lk.next = self.head
        #point first to new first node
        self.head = lk

    def deleteatend(self):
        linkedlist = self.head
        while linkedlist.next.next != None:
            linkedlist = linkedlist.next
        linkedlist.next = None
if __name__ == "__main__":
    linked_list = LinkedList()
    linked_list.insertatbegin(12)
    linked_list.insertatbegin(22)
    linked_list.insertatbegin(30)
    linked_list.insertatbegin(40)
    linked_list.insertatbegin(55)
    #print list
    print("Linked List: ", end="")
    linked_list.printList()
    linked_list.deleteatend()
    print("Linked List after deletion: ", end="")
    linked_list.printList()

输出

Linked List: 
[ 55  40  30  22  12 ]
Linked List after deletion: 
[ 55  40  30  22 ]

在给定位置删除

在链接的删除操作中，我们删除列表中任意位置的元素。

算法

1. START
2. Iterate until find the current node at position in the list
3. Assign the adjacent node of current node in the list to its previous node.
4. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");

   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void deletenode(int key){
   struct node *temp = head, *prev;
   if (temp != NULL && temp->data == key) {
      head = temp->next;
      return;
   }

   // Find the key to be deleted
   while (temp != NULL && temp->data != key) {
      prev = temp;
      temp = temp->next;
   }

   // If the key is not present
   if (temp == NULL) return;

   // Remove the node
   prev->next = temp->next;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(40);
   insertatbegin(55);
   printf("Linked List: ");

   // print list
   printList();
   deletenode(30);
   printf("\nLinked List after deletion: ");

   // print list
   printList();
}

输出

Linked List: 
[ 55  40  30  22  12 ]
Linked List after deletion: 
[ 55  40  22  12 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   cout << "\n[";

   //start from the beginning
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
   cout << "]";
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void deletenode(int key){
   struct node *temp = head, *prev;
   if (temp != NULL && temp->data == key) {
      head = temp->next;
      return;
   }

   // Find the key to be deleted
   while (temp != NULL && temp->data != key) {
      prev = temp;
      temp = temp->next;
   }

   // If the key is not present
   if (temp == NULL) return;

   // Remove the node
   prev->next = temp->next;
}
int main(){
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(44);
   insertatbegin(50);
   cout << "Linked List: ";

   // print list
   printList();
   deletenode(30);
   cout << "Linked List after deletion: ";
   printList();
}

输出

Linked List: 
[ 50  44  30  22  12 ]Linked List after deletion: 
[ 50  44  22  12 ]

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;
   
   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");
   
      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }
   
   //insertion at the beginning
   static void insertatbegin(int data) {

   
      //create a link
      node lk = new node(data);;

      // point it to old first node
      lk.next = head;

      //point first to new first node
      head = lk;
   }
   static void deletenode(int key) {
      node temp = head;
      node prev = null;
      if (temp != null && temp.data == key) {
         head = temp.next;
         return;
      }
      
      // Find the key to be deleted
      while (temp != null && temp.data != key) {
         prev = temp;
         temp = temp.next;
      }
      
      // If the key is not present
      if (temp == null) return;
      
      // Remove the node
      prev.next = temp.next;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatbegin(44);
      insertatbegin(50);
      insertatbegin(33);
      System.out.println("Linked List: ");

      // print list
      printList();

      //deleteatbegin();
      //deleteatend();
      deletenode(12);
      System.out.println("\nLinked List after deletion: ");

      // print list
      printList();
   }
}

输出

Linked List: 

[ 33  50  44  30  22  12 ]
Linked List after deletion: 

[ 33  50  44  30  22 ]

#python code for deletion at given position using linked list.
class Node:
    def __init__(self, data=None):
        self.data = data
        self.next = None
class LinkedList:
    def __init__(self):
        self.head = None
    # display the list
    def printList(self):
        p = self.head
        print("\n[", end="")
        #start from the beginning
        while(p != None):
            print(" ", p.data, " ", end="")
            p = p.next
        print("]")
    #insertion at the beginning
    def insertatbegin(self, data):
        #create a link
        lk = Node(data)
        # point it to old first node
        lk.next = self.head
        #point first to new first node
        self.head = lk
    def deletenode(self, key):
        temp = self.head
        if (temp != None and temp.data == key):
            self.head = temp.next
            return
        # Find the key to be deleted
        while (temp != None and temp.data != key):
            prev = temp
            temp = temp.next
        # If the key is not present
        if (temp == None):
            return
        # Remove the node
        prev.next = temp.next
llist = LinkedList()
llist.insertatbegin(12)
llist.insertatbegin(22)
llist.insertatbegin(30)
llist.insertatbegin(40)
llist.insertatbegin(55)
print("Original Linked List: ", end="")
# print list
llist.printList()
llist.deletenode(30)
print("\nLinked List after deletion: ", end="")
# print list
llist.printList()

输出

Linked List: 
[ 55  40  30  22  12 ]
Linked List after deletion: 
[ 55  40  22  12 ]

反向操作

这一行动是彻底的。我们需要让最后一个节点成为头节点所指向的，并反转整个链表。

首先，我们遍历到列表的末尾。它应该指向NULL。现在，我们将使其指向其前一个节点 -

我们必须确保最后一个节点不是最后一个节点。所以我们会有一些临时节点，它看起来像指向最后一个节点的头节点。现在，我们将使所有左侧节点一一指向其先前的节点。

除头节点所指向的节点（第一个节点）外，所有节点都应指向其前任节点，使它们成为新的后继节点。第一个节点将指向 NULL。

我们将使用临时节点使头节点指向新的第一个节点。

算法

反转链表的分步过程如下 -

1 START
2. We use three pointers to perform the reversing: prev, next, head.
3. Point the current node to head and assign its next value to the prev node.
4. Iteratively repeat the step 3 for all the nodes in the list.
5. Assign head to the prev node.

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");
   
   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void reverseList(struct node** head){
   struct node *prev = NULL, *cur=*head, *tmp;
   while(cur!= NULL) {
      tmp = cur->next;
      cur->next = prev;
      prev = cur;
      cur = tmp;
   }
   *head = prev;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(40);
   insertatbegin(55);
   printf("Linked List: ");

   // print list
   printList();
   reverseList(&head);
   printf("\nReversed Linked List: ");
   printList();
}

输出

Linked List: 
[ 55  40  30  22  12 ]
Reversed Linked List: 
[ 12  22  30  40  55 ]

#include <bits/stdc++.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");

   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void reverseList(struct node** head){
   struct node *prev = NULL, *cur=*head, *tmp;
   while(cur!= NULL) {
      tmp = cur->next;
      cur->next = prev;
      prev = cur;
      cur = tmp;
   }
   *head = prev;
}
int main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(40);
   insertatbegin(55);
   printf("Linked List: ");

   // print list
   printList();
   reverseList(&head);
   printf("\nReversed Linked List: ");
   printList();
   return 0;
}

输出

Linked List: 
[ 55  40  30  22  12 ]
Reversed Linked List: 
[ 12  22  30  40  55 ]

public class Linked_List {
   static Node head;
   static class Node {
      int data;
      Node next;
      Node (int value) {
         data = value;
         next = null;
      }
   }

   // display the list
   static void printList(Node node) {
      System.out.print("\n[");

      //start from the beginning
      while(node != null) {
         System.out.print(" " + node.data + " ");
         node = node.next;
      }
      System.out.print("]");
   }
   static Node reverseList(Node head) {
      Node prev = null;
      Node cur = head;
      Node temp = null;
      while (cur != null) {
         temp = cur.next;
         cur.next = prev;
         prev = cur;
         cur = temp;
      }
      head = prev;
      return head;
   }
   public static void main(String args[]) {
      Linked_List list = new Linked_List();
      list.head = new Node(33);
      list.head.next = new Node(50);
      list.head.next.next = new Node(44);
      list.head.next.next.next = new Node(22);
      list.head.next.next.next.next = new Node(12);
      System.out.println("Linked List: ");
      
      // print list
      list.printList(head);
      head = list.reverseList(head);
      System.out.println("\nReversed linked list ");
      list.printList(head);
   }
}

输出

Linked List: 
[ 33  50  44  22  12 ]
Reversed linked list 

[ 12 22  44  50  33 ]

class Node:
   def __init__(self, data=None):
      self.data = data
      self.next = None

class SLL:
   def __init__(self):
      self.head = None

# Print the linked list
   def listprint(self):
      printval = self.head
      print("Linked List: ")
      while printval is not None:
         print (printval.data)
         printval = printval.next
   def reverse(self):
      prev = None
      curr = self.head
      while(curr is not None):
         next = curr.next
         curr.next = prev
         prev = curr
         curr = next
      self.head = prev

l1 = SLL()
l1.head = Node("731")
e2 = Node("672")
e3 = Node("63")

l1.head.next = e2
e2.next = e3

l1.listprint()
l1.reverse()
print("After reversing: ")
l1.listprint()

输出

Linked List: 
731
672
63
After reversing: 
Linked List: 
63
672
731

搜索操作

使用关键元素在列表中搜索元素。这个操作和数组查找的方式是一样的；将列表中的每个元素与给定的关键元素进行比较。

算法

1 START
2 If the list is not empty, iteratively check if the list contains the key
3 If the key element is not present in the list, unsuccessful search
4 END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   printf("\n[");

   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
int searchlist(int key){
   struct node *temp = head;
   while(temp != NULL) {
      if (temp->data == key) {
         return 1;
      }
      temp=temp->next;
   }
   return 0;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(40);
   insertatbegin(55);
   printf("Linked List: ");

   // print list
   printList();
   k = searchlist(30);
   if (k == 1)
      printf("\nElement is found");
   else
      printf("\nElement is not present in the list");
}

输出

Linked List: 
[ 55  40  30  22  12 ]
Element is found

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// display the list
void printList(){
   struct node *p = head;
   cout << "\n[";

   //start from the beginning
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
   cout << "]";
}

//insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
int searchlist(int key){
   struct node *temp = head;
   while(temp != NULL) {
      if (temp->data == key) {
         return 1;
      }
      temp=temp->next;
   }
   return 0;
}
int main(){
   int k = 0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   insertatbegin(44);
   insertatbegin(50);
   cout << "Linked List: ";

   // print list
   printList();
   k = searchlist(16);
   if (k == 1)
      cout << "\nElement is found";
   else
      cout << "\nElement is not present in the list";
}

输出

Linked List: 
[ 50  44  30  22  12 ]
Element is not present in the list

public class Linked_List {
   static class node {
      int data;
      node next;
      node (int value) {
         data = value;
         next = null;
      }
   }
   static node head;

   // display the list
   static void printList() {
      node p = head;
      System.out.print("\n[");

      //start from the beginning
      while(p != null) {
         System.out.print(" " + p.data + " ");
         p = p.next;
      }
      System.out.print("]");
   }

   //insertion at the beginning
   static void insertatbegin(int data) {

      //create a link
      node lk = new node(data);;

      // point it to old first node
      lk.next = head;
      
      //point first to new first node
      head = lk;
   }
   static int searchlist(int key) {
      node temp = head;
      while(temp != null) {
         if (temp.data == key) {
            return 1;
         }
         temp=temp.next;
      }
      return 0;
   }
   public static void main(String args[]) {
      int k=0;
      insertatbegin(12);
      insertatbegin(22);
      insertatbegin(30);
      insertatbegin(44);
      insertatbegin(50);
      insertatbegin(33);
      System.out.println("Linked List: ");

      // print list
      printList();
      k = searchlist(44);
      if (k == 1)
         System.out.println("\nElement is found");
      else
         System.out.println("\nElement is not present in the list");
   }
}

输出

Linked List: 

[33  50  44  30  22  12 ]
Element is found

class Node:
   def __init__(self, data=None):
      self.data = data
      self.next = None

class SLL:
   def __init__(self):
      self.head = None
   def search(self, x):
      count = 0
      
      # Initialize current to head
      current = self.head

      # loop till current not equal to None
      while current != None:
         if current.data == x:
            print("data found")
            count = count + 1
         current = current.next
      if count == 0:
         print("Data Not found")

l1 = SLL()
l1.head = Node("731")
e2 = Node("672")
e3 = Node("63")

l1.head.next = e2
e2.next = e3

l1.search("63")

输出

data found

遍历操作

遍历操作按顺序遍历列表中的所有元素并按该顺序显示元素。

算法

1. START
2. While the list is not empty and did not reach the end of the list, print the data in each node
3. END

例子

以下是此操作在各种编程语言中的实现 -

C C++ Java Python

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

   // display the list
   void printList(){
   struct node *p = head;
   printf("\n[");

   //start from the beginning
   while(p != NULL) {
      printf(" %d ",p->data);
      p = p->next;
   }
   printf("]");
}

   //insertion at the beginning
   void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first node
   head = lk;
}
void main(){
   int k=0;
   insertatbegin(12);
   insertatbegin(22);
   insertatbegin(30);
   printf("Linked List: ");

   // print list
   printList();
}

输出

Linked List: 
[ 30  22  12 ]

#include <bits/stdc++.h>
#include <string>
using namespace std;
struct node {
   int data;
   struct node *next;
};
struct node *head = NULL;
struct node *current = NULL;

// Displaying the list
void printList(){
   struct node *p = head;
   while(p != NULL) {
      cout << " " << p->data << " ";
      p = p->next;
   }
}

// Insertion at the beginning
void insertatbegin(int data){

   //create a link
   struct node *lk = (struct node*) malloc(sizeof(struct node));
   lk->data = data;

   // point it to old first node
   lk->next = head;

   //point first to new first